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JEE Advanced 2019: Every institute will release its own cut-off to enrol students but to be considered pass, one needs to secure the minimum marks as described in the official notification

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JEE Advanced 2019: Result on June 14, 2019

JEE Advanced 2019: As the Joint Entrance Examination (JEE) result 2019 has been announced on June 14, the counselling schedule will be released soon. While the JEE Advanced is considered to be the entrance gateway to the Indian Institutes of Technology (IITs), there are many central institutes which consider the JEE Advanced score to enroll students.

Every institute will release its own cut-off to enroll students but to be considered pass, one needs to secure the minimum marks as described in the official notification released by the IIT Roorkee — which is conducting the exam this year. To be considered successful, a candidate needs to score a minimum percentage.

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– Indian Institute of Science, Bangalore (IISc)

— Indian Institutes of Science Education and Research (IISERs) located in Berhampur, Bhopal, Kolkata, Mohali, Pune, Thiruvananthapuram and Tirupati

— Indian Institute of Space Science and Technology (IIST), Thiruvananthapuram

— Rajiv Gandhi Institute of Petroleum Technology (RGIPT), Rae Bareli

— Indian Institute of Petroleum & Energy, Visakhapatnam

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In 2019, out of 11.47 lakh JEE Main candidates, 2.45 lakh students qualified for the JEE Advanced but only 1.73 lakh registered for the same. In 2018, out of 2.31 lakh students who qualified for the exam, 1.65 lakh candidates chose to register for it.

This year, Mumbai’s Kartikey Gupta has secured all India rank (AIR) 1in JEE Advanced. He obtained 346 marks out of 372 marks. Gupta scored rank 18 in the JEE Main April exam this year.

First uploaded on: 15-06-2019 at 11:30 IST

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